Question

If $2+i\sqrt{3}$ is a root of the equation $x^2+px+q=0$, where p and q are real, then (p, q) =

• A. (-4,7)
• B. (4,7)
• C. (4,7)
• D. (-4,-7)

Answer 1

The correct option is A

(-4,7)

Since $2+i\sqrt{3}$ is a root, therefore $2-i\sqrt{3}$ will be other root. Now sum of the roots = 4 = -p and product of roots = 7 = q. Hence (p, q) = (-4, 7).