Question

If $2$ is a root of $k{x}^4-11x^3+k{x}^2+13x+2$, what is the value of $k$?

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is C $3$

$f\left(2\right)=k\times (2{)}^4-11\times (2{)}^3+k\times (2{)}^2+13\times 2+2$

$f\left(2\right)=0$

$16k-88+4k+26+2=0$
$20k-88+28=0$
$20k-60=0$
$20k=60$
$k=3$