if 2 is a root of the equation p2x2−5qx−6q=0(p,q∈R) then the roots of the equation x2+px+q=0 are
Rational and equal
2 is a root of the equation p2x2−5qx−6q=0
Substituting 2 in the equation, we get
4p2−10q−6q=0
⇒4(p2−4q)=0
Or p2−4q=0
The discriminant of the equation x2+px+q is p2−4q=0
So the roots of the equation are equal and rational