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Question

If 2 is a zero of the polynomial p(x)=2x23x+7a, find the value of a

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Solution

Given polynomial p(x)=2x23x+7a is zero polynomial if x is 2
Replace x by 2 we get
2(2)23(2)+7a=0
2×43×2+7a=0
86+7a=0
2+7a=0
Add -2 both sides we get
2+7a2=02
7a=2
Divided by 7 both side we get
a=27
So a=27

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