If 2 is the root of the quadratic equation x2+p2x+6=0 . Find the value of (pi)2
If 2 is the root it should satisfy the quadratic equation.
(2)2+p2(2)+6=0
4+2p2+6=0
2p2=−10
p2=−5
(pi)2=5
If 2 is the root of the quadratic equation x2+p2x+6=0, then the value of (pi)2 (where i=√−1) is