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Question

If 2rn, then nCr+2nCr1+nCr2 is equal to:

A
n+1Cr+1
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B
2n+1Cr+1
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C
2n+2Cr
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D
n+2Cr
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Solution

The correct option is C n+2Cr
The value of nCr+2nCr1+nCr2 is
= nCr+nCr1+nCr1+nCr2 .....Using mCx+mCx1=m+1Cx
= n+1Cr+n+1Cr1
= n+2Cr

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