Question

If $2\log y-\log x-3=0$ and $x=\frac{y^2}{m}$, then the value of $m$ is equal to

• A. $1000$
• B. $455$
• C. $125$
• D. $735$

Answer 1

The correct option is A $1000$

$2\log y-\log x-3=0\log x=2\log y-3\text{Assuming base 10}{\log }_{10}x=2{\log }_{10}y-3{\log }_{10}10{\log }_{10}x={\log }_{10}\left(\frac{y^2}{{10}^3}\right)\text{Removing log}x=\frac{y^2}{1000}\therefore m=1000$