Question

If 2 mL of acetone is present in 45 mL of its aqueous solution, calculate the concentration of this solution.

Answer 1

Volume of solute (acetone) = 2 mL
Volume of solution (solute+solvent) = 45 mL

$$\begin{gathered} \mathrm{Concentration}\mathrm{of}\mathrm{solution}=\frac{\mathrm{Volume}\mathrm{of}\mathrm{solute}}{\mathrm{Volume}\mathrm{of}\mathrm{solution}}\times 100 \\ \mathrm{Concentration}\mathrm{of}\mathrm{solution}=\frac{2}{45}\times 100 \\ \mathrm{Concentration}\mathrm{of}\mathrm{solution}=4.44\% \end{gathered}$$