If 2 moles of an ideal monoatomic gas at temperature T0 is mixed with 4 moles of another ideal monoatomic gas at temperature 2T0, then the temperature of the mixture is
A
53T0
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B
32T0
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C
43T0
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D
54T0
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Solution
The correct option is A53T0 For the internal energy of mixture, Umix=(n1+n2)fRT2 Degree of freedom f will be same for both gases and the mixture as gases mixed are monoatomic. For the mixture we can apply, Umix=U1+U2 ⇒(n1+n2)fRT2=n1fRT02+n2fR×2T02 ⇒(n1+n2)T=n1T0+2n2T0 ⇒(2+4)T=2T0+8T0 ∴T=10T06=53T0