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If 2n=1024,...

Question

If $2^{n} = 1024$ , then $n = ?$

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Solution

$2^{n} = 1024 = 2^{10} \Rightarrow n = 10$

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Similar questions

\sqrt{2^{n}} = 1024

3^{(\frac{n}{4} - 4)}

If $\sqrt{2^{n}} = 1024, t h e n 3^{2 (\frac{n}{4} - 4)}$ =

\sqrt{2^{n}} = 1024,

{3^{2}}^{(\frac{n}{4} - 4)} =

(a) 3

(b) 9

(c) 27

(d) 81

a = \infty \sum n = 1 \frac{2 n}{(2 n - 1)!}, b = \infty \sum n = 1 \frac{2 n}{(2 n + 1)!}

a b

\frac{^{n} C_{0}}{2^{n}} + 2. \frac{^{n} C_{1}}{2^{n}} + 3. \frac{^{n} C_{2}}{2^{n}} + \dots . (n + 1) \frac{^{n} C_{n}}{2^{n}} = 16

, then the value of '

n

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