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Question
If 2 raised to a=3raised to b=6 raised to c, find the relationship between A,B and C.
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Solution
2^a=3^b=6^c=K
2=k^1/a 3=k^1/b 6=k^1/c
now we know that 3*2=6
so k^1/b*k^1/a=k^1/c
equating the basses
1/b+1/a=1/c
b+a/ba=1/c
ba/a+b=c
2=k^1/a 3=k^1/b 6=k^1/c
now we know that 3*2=6
so k^1/b*k^1/a=k^1/c
equating the basses
1/b+1/a=1/c
b+a/ba=1/c
ba/a+b=c
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