If 2secθ cosec θ−cotθ=3, then the value of tanθ is/are
A
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B12 2secθ cosec θ−cotθ=3
Dividing the equation by cotθ, ⇒2sec2θ−1=3tanθ ⇒2(1+tan2θ)−1=3tanθ ⇒2tan2θ−3tanθ+1=0⇒(2tanθ−1)(tanθ−1)=0 ⇒tanθ=1,12