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Question

If 2secθ cosec θcotθ=3, then the value of tanθ is/are

A
1
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B
12
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C
13
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D
14
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Solution

The correct option is B 12
2secθ cosec θcotθ=3
Dividing the equation by cotθ,
2sec2θ1=3tanθ
2(1+tan2θ)1=3tanθ
2tan2θ3tanθ+1=0(2tanθ1)(tanθ1)=0
tanθ=1,12

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