Question

If 2 sin 2θ =$\sqrt{3}$, prove that θ = 30°.

Answer 1

$$\begin{gathered} \text{2sin}\left(\text{2}\theta \right)=\sqrt{3} \\ =>\text{sin}\left(\text{2}\theta \right)=\frac{\sqrt{3}}{2} \\ =>\text{sin}\left(\text{2}\theta \right)=\sin \left({60}^0\right) \\ =>2\theta ={60}^0 \\ =>\theta =\frac{{60}^0}{2} \\ =>\theta ={30}^0 \end{gathered}$$