Question

If $2\sin 2\theta =\sqrt{3}$, then $\tan \theta$ is

• A. 1
• B. $\frac{1}{\sqrt{3}}$
• C. $\sqrt{3}$
• D. $\frac{1}{\sqrt{2}}$

Answer 1

Answer: (B)

$\frac{1}{\sqrt{3}}$

$sin2\theta =\frac{\sqrt{3}}{2}\Rightarrow sin2\theta =sin{60}^o\Rightarrow \theta ={30}^o$
$\therefore tan30=\frac{1}{\sqrt{3}}$