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Question

If 2sinαcosβsinγ=sinβsin(α+γ), then tanα,tanβ,tanγ are in

A
AP
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B
GP
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C
HP
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D
none of these
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Solution

The correct option is B HP
2sinαcosβsinγ=sinβ(sinαcosγ+cosαsinγ)
2sinαcosβsinγ=sinβsinαcosγ+sinβcosαsinγ
Dividing on both sides with (sinαsinβsinγ) gives
2tanβ=1tanα+1tanγ
tanα,tanβ,tanγ are in HP

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