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Question

If 2sinCcosA=sinB, then ABC is

A
Isosceles triangle
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B
equilateral triangle
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C
right angle triangle
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D
none of the options
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Solution

The correct option is A Isosceles triangle
2sinCcosA=sinBsin(C+A)+sin(CA)=sinB
We know that,
A+B+C=π
sinB+sin(CA)=sinBsin(CA)=0C=A

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