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Question

If 2sinθ+tanθ=0, then the general values of θ are


A

2nπ±π3

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B

nπ,2nπ±2π3

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C

nπ,2nπ±π3

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D

nπ,nπ+2π3

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Solution

The correct option is B

nπ,2nπ±2π3


Explanation for the correct option:

Find the value of θ:

Given,

2sinθ+tanθ=0

2sinθ+sinθcosθ=0

2sinθcosθ+sinθ=0

sinθ(2cosθ+1)=0

sinθ=0,2cosθ+1=0

sinθ=0,cosθ=-1/2

θ=nπ,cosθ=cos2π3

θ=nπ,2nπ±2π3

Hence, Option ‘B’ is Correct.


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