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Question

If 2sinx+10 and xϵ[0,2π], then the solution set for x is

A
[0,7π6]
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B
[0,7π6][11π6,2π]
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C
[11π6,2π]
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D
none of these
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Solution

The correct option is B [0,7π6][11π6,2π]
2sinx+10sinx12
Also we know 1sinx1
considering both solution,
12sinx1
Hence solution in the given interval is,
x[0,7π6][11π6,2π]


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