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Question

If 2tanA=3, then find the value of 4sinA+5cosA6sinA+2cosA

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Solution

2tanA=3 tanA=32
sinA=313 & cosA=213

4sinA+5cosA6sinA+2cosA=12+1018+4=2222=1

Hence, the answer is 1.


1178693_1263683_ans_28e9a5c25b8f4a67b7d379d245a07afa.png

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