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Question

If 2tan2θ=sec2θ, then the general value of θ is


A

nπ+π4

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B

nπ-π4

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C

nπ±π4

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D

2nπ±π4

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Solution

The correct option is C

nπ±π4


Explanation for the correct option:

Find the value of θ:

Given,

2tan2θ=sec2θ

2sin2θcos2θ=1cos2θ

2sin2θ=1

sin2θ=12

sinθ=±12

θ=nπ±π4

Hence, Option ‘B’ is Correct.


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