If 2tan2θ=sec2θ, then the general value of θ is
nπ+π4
nπ-π4
nπ±π4
2nπ±π4
Explanation for the correct option:
Find the value of θ:
Given,
2tan2θ=sec2θ
⇒2sin2θcos2θ=1cos2θ
⇒ 2sin2θ=1
⇒ sin2θ=12
⇒ sinθ=±1√2
∴θ=nπ±π4
Hence, Option ‘B’ is Correct.
If √3 cosθ+sinθ=√2,then general value of θ is