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Question

If |(2|x1|2)|1, then x

A
(,12][52,)
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B
(,12][12,32][52,)
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C
[12,32][52,)
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D
(,12][12,32]
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Solution

The correct option is B (,12][12,32][52,)
|(2|x1|2)|1|(|x1|1)|12
Let |x1|1=t|t|12
t12 or t12
|x1|112 or |x1|112
|x1|12 or |x1|32
(x1)[12,12] or (x1)(,32][32,)
x[12,32] or x(,12][52,)

x(,12][12,32][52,)

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