If 2 x 2 - 3 x y - y 2 - x - 2 y - 8 - 0 - then d y d x is equal to

The correct option is A 3 y + 4 x + 1 2 y + 3 x 2 2x ^ 2 3xy+ y ^ 2 +x+2y 8=0 4x 3x dy dx 3y+2y dy dx +1+2 dy dx =0 ( 4x 3y+1 ) ...

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Division Algorithm for a Polynomial

If 2 x 2 -...

Question

If $2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0,$ then $\frac{d y}{d x}$ is equal to

\frac{- 3 y + 4 x + 1}{- 2 y + 3 x - 2}

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\frac{3 y + 4 x + 1}{2 y + 3 x + 2}

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\frac{3 y - 4 x + 1}{2 y - 3 x - 2}

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\frac{3 y - 4 x + 1}{2 y + 3 x + 2}

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Solution

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$I f 2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0 t h e n \frac{d y}{d x} =$

x^{2} y^{2} - 2 x y^{2} - 3 y^{2} - 4 x^{2} y + 8 x y + 12 y = 0

x + 2 y = 5

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