Question

If $2x^2-\left(2+k\right)x+k=0$ where $k$ is a real number, find the roots of the equation.

Answer 1

$2x^2-(2+k)x+k=0$

$2x^2-2x-kx+k=0$

$2x(x-1)-k(x-1)=0$

$(x-1)(2x-k)=0$

$x=1,\frac{K}{2}$

are roots of this equations.