If $2 x^{2} + p x + 6 = (2 x - a) (x - 2)$ Find the value of $a, p .$

a = 3

and

p = - 7

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a = - 3

and

p = 7

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a = - 3

and

p = - 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a = 3

and

p = 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A $a = 3$ and $p = - 7$
$2 x^{2} + p x + 6 = (2 x - a) (x - 2) 2 x^{2} + p x + 6 = {2 x}^{2} - (4 + a) x + 2 a b y c o m p a r i n g c o e f f i c i e n t s, p = - 4 - a 6 = 2 a h e n c e f r o m t h e a b o v e e q u a t i o n s, a = 3 a n d p = - 7$

Suggest Corrections

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