If 2x - 3- 42x - 5 - 23x - 7- then the value of x is

The correct option is C 7 2^x + 3· 4^2x 5 = 2^3x + 7 ⇒ 2^x + 3· 2^4x 10 = 2^3x + 7 ⇒ 5x 7 = 3x + 7 ⇒ x = 7 ...

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Relation between AM,GM,HM for 2 Numbers

If 2x + 3· ...

Question

If $2^{x + 3} \cdot 4^{2 x - 5} = 2^{3 x - 7}$ , then the value of $x$ is

3

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4

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6

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7

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4 (2 x - 13) - 9 (x - 3) + 2 (3 x - 10) = 0

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{log}_{(2 x + 3)} (6 x^{2} + 23 x + 21) = 4 - {log}_{(3 x + 7)} (4 x^{2} + 12 x + 9)

4 x + 1

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2^{x + 1} = 4^{x - 3}

2^{5 x + 3} = 8^{x + 3}

4^{2 x} = \frac{1}{32}

4^{x - 1} \times {(0.5)}^{3 - 2 x} = {(\frac{1}{8})}^{x}

2^{3 x - 7} = 256

f : [- 3, 7) \to R

f (x) =

⎛ ⎜ ⎝ \begin{matrix} 4 x^{2} - 1; - 3 \leq x < 2 3 x - 2; 2 \leq x \leq 4 2 x - 3; 4 < x < 7 \end{matrix}

\frac{f (3) + f (- 1)}{2 f (6) - f (1)}

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