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Question

If 2x=3y=6z, Prove that (1x+1y1z=0)

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Solution

2x=3y=6z=k
x=log2ky=log3kz=log6k
1x=logk21y=logk31z=logk6
1x+1y1z=logk2+logk3logk6
=logk6logk6
=0

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