Question

If $2^x\cdot {32}^x=100$ (given $\log 2=0.3010$ and $\log 0.4771)$, then the value of $x$ is

• A. $1.49$
• B. $1.59$
• C. $1.69$
• D. $1.79$

Answer 1

The correct option is A $1.49$

$2^x.{32}^x=100\Rightarrow 2^x.2^{5x}=100\Rightarrow 2^{6x}={10}^2$.
Taking $\log x=\frac{2}{6\log 2}=1.49$.