If 2 zeroes of a cubic polynomial are 0 , then it has no linear or constant terms

True

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False

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Solution

The correct option is B
False

$α β + β γ + γ α$ = $\frac{c}{a}$ , $α β γ$ = $- \frac{d}{a}$ , Hence if $α, β$ = 0, c, d = 0

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Similar questions

Q. Question 2 (iv)
Are the following statements ‘True’ or False’? Justify your answer.
iv) If two of the zeroes of a cubic polynomial are zero, then it does not have linear and constant terms.

If one of the zeroes of a quadratic polynomial of the form $x^{2} + a x + b$ is the negative of the other, then it
(A) has no linear term and the constant term is negative.
(B) has no linear term and the constant term is positive.
(C) can have a linear term but the constant term is negative.
(D) can have a linear term but the constant term is positive.

Q. If one of the zeroes of a quadratic polynomial of the form

x^{2} + a x + b

is the negative of the other , then it
(a) has no linear term and constant term is negative.
(b) has no linear term and the constant term is positive.
(c) can have a linear term but the constant term is negative .
(d) can have a linear term but the constant term is positive .

Q. If two of the zeroes of a cubic polynomial are zero, then it does not have ______ and _______ terms.

Say true or false.

If all the zeroes of a cubic polynomial are negative, then all the coefficients and the constant term of the polynomial have the same sign.

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If 2 zeroes of a cubic polynomial are 0 , then it has no linear or constant terms

The correct option is B False αβ+βγ+γα = ca, αβγ = −da, Hence if α,β = 0, c, d = 0

The correct option is B
False

$α β + β γ + γ α$ = $\frac{c}{a}$ , $α β γ$ = $- \frac{d}{a}$ , Hence if $α, β$ = 0, c, d = 0