If 20.0 mL of 1.0 M calcium chloride and 60 mL of 0.2 M calcium chloride are mixed, what will be the molarity of the final solution?

0.20 M

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0.30 M

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0.40 M

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0.50 M

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Solution

The correct option is C 0.40 M
$\begin{matrix} Resultant Molarity M_{r} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{20 \times 1 + 60 \times 0.2}{20 + 60} = 0.40 M Correct answer is 0.40 M \end{matrix}$

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If 20.0 mL of 1.0 M calcium chloride and 60 mL of 0.2 M calcium chloride are mixed, what will be the molarity of the final solution?

The correct option is C 0.40 M Resultant Molarity Mr=M1V1+M2V2V1+V2=20×1+60×0.220+60=0.40M Correct answer is 0.40M

The correct option is C 0.40 M
$\begin{matrix} Resultant Molarity M_{r} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{20 \times 1 + 60 \times 0.2}{20 + 60} = 0.40 M Correct answer is 0.40 M \end{matrix}$