If: [−20,20]→R defined by f(x)=[x2a]sinx+cosx is an even function, then the set of value of 'a'. (where [⋅] denotes the greatest integral function.) is aϵ(5b,∞) Find b
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Solution
For given function to be even, [x2a]=0∀x∈[−20,20] ⇒0≤x2a<1⇒a>x2∀x∈[−20,20]⇒a>202=400 ∴a∈(40,∞). Hence b=8