If 20 cuboids of length 20 cm, breadth 8 cm and height 2 cm are molten to be casted into a cube, find the length of the side of the cube.

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Solution

$Volume of 1 cuboid = (20 \times 8 \times 2) {cm}^{3} = 320 {cm}^{3} Volume of 200 cuboids = (20 \times 320) {cm}^{3} = 64000 {cm}^{3} Volume of the cube so formed = 64000 {cm}^{3} \Rightarrow {(Side of the cube)}^{3} = 64000 {cm}^{3} \Rightarrow Side of the cube = 40 cm, since 40^{3} = 64000$

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If 20 cuboids of length 20 cm, breadth 8 cm and height 2 cm are molten to be casted into a cube, find the length of the side of the cube.

Volume of 1 cuboid = (20×8×2) cm3=320 cm3Volume of 200 cuboids = (20×320) cm3 = 64000 cm3Volume of the cube so formed = 64000 cm3⇒(Side of the cube)3 = 64000 cm3⇒Side of the cube = 40 cm, since 403 = 64000

$Volume of 1 cuboid = (20 \times 8 \times 2) {cm}^{3} = 320 {cm}^{3} Volume of 200 cuboids = (20 \times 320) {cm}^{3} = 64000 {cm}^{3} Volume of the cube so formed = 64000 {cm}^{3} \Rightarrow {(Side of the cube)}^{3} = 64000 {cm}^{3} \Rightarrow Side of the cube = 40 cm, since 40^{3} = 64000$