If 20 mL of ethanol density - 0-7893 g-mL is mixed with 40 mL water density - 0-9971 g-mL at 25-C- the final solution has density of 0-9571 g-mL- Calculate the molality of alcohol in the final solution- as nearest integer

C_2H_5OH⟶ V_1 = 20 mL, d_1 = 0.7893 g/mL m_1 = 15.786 g H_2O→ V_2 = 40 mL, d_2 = 0.9971 g/mL m_2 = 39.884 g Total mass = 55.65 g d ...

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Molality

If 20 mL of...

Question

If $20 m L$ of ethanol (density $= 0.7893 g / m L$ ) is mixed with $40 m L$ water (density $= 0.9971 g / m L$ ) at $25^{\circ} C$ ,
the final solution has density of $0.9571 g / m L$ .
Calculate the molality of alcohol in the final solution. (as nearest integer)

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10

= 0.7893 g m L^{- 1})

20

0.9971 g m L^{- 1})

25^{o} C

0.9571 g m L^{- 1}

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= 0.789 m L^{- 1}

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