Question

If 20 percent managers are technocrats, the probability that a random committee of 5 managers consists of exactly 2 technocrats is

• A. 0.2048
• B. 0.4000
• C. 0.4096
• D. 0.9421

Answer 1

The correct option is A 0.2048

We use binomial distribution
$p$ = 20% = 0.2; $q=80$
= 0.8; n = 5
Probability of exactly 2 technocrats is P(x=2)
$P={}^5{C}_2{(0.2)}^2{(0.8)}^3$
$P=0.2048$