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pH of a Solution

If 200 mL of ...

Question

If 200 mL of a 0.031 molar solution of $H_{2} S O_{4}$ are added to 84 rall. of a 0.150 M $K O H$ solution, what is the pH of the resulting solution ?

12.4

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1.7

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2.2

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10.9

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Solution

The correct option is D 10.9
mmol of $H^{+}$ (initial) $= 200 \times 0.031 \times 2 = 124$
mmol of $O H^{-}$ (initial) $= 84 \times 0.15 = 12.6$
mmol of $O H^{-}$ (left) after neutralisation $= 0.2 [O H^{-}]_{f i n a l} = \frac{0.2}{284} = 7 \times 10^{- 4} M$
$p O H = 3.15$ and $p H = 10.85$

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