Question

If 2009 = $p^a.q^b$ where p and q are prime numbers then find the value of p + q

• A. 3
• B. 48
• C. 51
• D. 2009

Answer 1

The correct option is B 48

Given $2009=p^a{q}^b$ ...(i)
Where p and q are prime numbers
We know that $2009=7\times 7\times 41=7^2\times {41}^1$ ...(ii)
Comparing equation (1) and (2) we get
$p=7,q=41,a=2andb=1$
$\therefore p+q=7+41=48$