You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Ideal Gas Equation

If 200mL of...

Question

If $200 m L$ of $N_{2}$ at $25^{0} C$ and a pressure of $250 m m$ are mixed with $350 m L$ of $O_{2}$ at $25^{0} C$ and a pressure of $300 m m$ so that , the volume of resulting mixture is $300 m L$ . What would be the final pressure of the mixture at $25^{0} C$ ?

Open in App

Solution

Number of mole of $N_{2} . n_{1} = \frac{P_{1} v_{1}}{T_{1}}$
Number of mole of $O_{2} . n_{2} = \frac{P_{2} V_{2}}{T_{2}}$
After mixing number of mole $n_{3} = \frac{P_{2} V_{3}}{T_{3}}$
$n_{1} + n_{2} = n_{3}$
$\frac{P_{1} V_{1}}{T_{1}} + \frac{P_{2} V_{2}}{T_{2}} = \frac{P_{3} V_{3}}{T_{3}}$
$dfrac(250 mm)×(200 ml)(25oC+273)+(300 mm)×(350 ml)(28oC+273)=P3×300 ml(25oC+273)$
$\frac{250 \times 200 + 300 \times 350}{360} = P_{3}$
$\frac{1000 (50 + 105)}{300} = P_{3}$
$P_{3} = 518.33 a t m$

Suggest Corrections

Similar questions

Q. If 200 mL of N

_{2}

at 25

^{\circ} C

and a pressure of 250 mm are mixed with 350 mL of O

_{2}

at 25

^{\circ} C

and a pressure of 300 mm so that, the volume of resulting mixture is 300 mL, what would be the final pressure of the mixture at 25

^{\circ} C

100 m l

of gas A at

200 m m

pressure and

200 m l

of gas at

50 m m

pressure are mixed in a container of

300 m l

then the resultant pressure of gas mixture will be (Assume gases do not combine).

Q. 5 litre of

N_{2}

under a pressure of 2 atm, 2 litre of

O_{2}

at 5.5 atm and 3 litre of

C O_{2}

at 5 atm are mixed. The resultant volume of the mixture is 15 litre. Calculate the total pressure of the mixture and partial pressure of each constituent.

125 m L

of a gas

A

of pressure

500 m m

is mixed with

200 m L

of another gas

B

at a pressure of

300 m m

in a vessel of

150 m L

capacity. What will be the total pressure of the resulting mixture if the temperature is kept constant?

If $250 m L$ of $N_{2}$ over water at $30^{\circ} C$ and a total pressure of $740 t o r r$ is mixed with $300 m L$ of $N e$ over water at $25^{\circ} C$ and a total pressure of $780 t o r r$ , what will be the total pressure if the mixture is in a $500 m L$ vessel over water at $35^{\circ} C$ .

(Given : Vapour pressure (Aqueous tension) of $H_{2} O$ at $25^{\circ} C, 30^{\circ} C$ and $35^{\circ} C$ are $23.8, 31.8$ and $42.2 t o r r$ respectively. Assume volume of $H_{2} O (l)$ is negligible in final vessel)

Join BYJU'S Learning Program

If 200mL of N2 at 250C and a pressure of 250mm are mixed with 350mL of O2 at 250C and a pressure of 300mm so that , the volume of resulting mixture is 300mL. What would be the final pressure of the mixture at 250C?

Number of mole of N2.n1=P1v1T1Number of mole of O2.n2=P2V2T2After mixing number of mole n3=P2V3T3n1+n2=n3P1V1T1+P2V2T2=P3V3T3dfrac(250 mm)×(200 ml)(25oC+273)+(300 mm)×(350 ml)(28oC+273)=P3×300 ml(25oC+273)250×200+300×350360=P31000(50+105)300=P3P3=518.33 atm

If $200 m L$ of $N_{2}$ at $25^{0} C$ and a pressure of $250 m m$ are mixed with $350 m L$ of $O_{2}$ at $25^{0} C$ and a pressure of $300 m m$ so that , the volume of resulting mixture is $300 m L$ . What would be the final pressure of the mixture at $25^{0} C$ ?