You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dalton's Law of Partial Pressures

If 200mL of...

Question

If $200 m L$ of $N_{2}$ at $25^{o} C$ and a pressure of $250 m m$ are mixed with $350 m L$ of $O_{2}$ at $25^{o} C$ and a pressure of $300 m m$ so that, the volume of resulting mixture is $300 m L$ , what would be the final pressure of the mixture at $25^{o} C$ ?

Open in App

Solution

$P_{1} = 250 P_{2} = 300 V_{f} = 300 V_{1} = 200 V_{2} = 350 P_{f} = ? P_{1} V_{1} + P_{2} V_{2} = P_{f} V_{f} \Rightarrow (250) (200) + (300) (350) = P_{f} (300) \Rightarrow P_{f} = \frac{350 (300)}{300} + \frac{250 \times 200}{300} = 350 + \frac{500}{3} = 516.66 m m \Rightarrow Final Pressure of the mixture= 516.66 mm$

Suggest Corrections

Similar questions

N_{2}

25^{o} C

O_{2}

25^{o} C

25^{o} C

_{2}

^{\circ} C

_{2}

^{\circ} C

^{\circ} C

25^{o} C

25^{o} C

25^{o} C

N_{2} O_{4}

{N O}_{2}

0.7

0.3

25^{o} C

10

100 m l

200 m m

200 m l

50 m m

300 m l

Join BYJU'S Learning Program