If $2018$ is divided into three parts proportional to $3, 11$ and $14$ parts then the largest part is

\frac{2018}{3}

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\frac{2018}{14}

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\frac{2018}{11}

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1009

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Solution

The correct option is C $1009$
Let we divide $2018$ in $3 x, 11 x$ and $14 x$ respectively.

$∴ 3 x + 11 x + 14 x = 2018$
$⟹ 28 x = 2018 ⟹ x = \frac{2018}{28}$

The largest part is $14 = 14 \times \frac{2018}{28} = 1009$

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