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Standard XII

Chemistry

Borax

If 20g of w...

Question

If $20 g$ of water at $60^{0} C$ is mixed with $60 g$ of water at $20^{0} C$ . The resultant temperature is :

60^{0} C

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20^{0} C

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30^{0} C

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0^{0} C

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Solution

The correct option is A $30^{0} C$
Heat lost by the hot water $=$ Heat gained by the cold water.
$m_{1} c Δ T_{1} = m_{2} c Δ T_{2}$
$20 (60 - T) = 60 (T - 20)$
$60 - T = 3 T - 60$
$4 T = 120$
$T = 30^{o} C$

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If 20g of water at 600C is mixed with 60g of water at 200C. The resultant temperature is :

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If $20 g$ of water at $60^{0} C$ is mixed with $60 g$ of water at $20^{0} C$ . The resultant temperature is :

The correct option is A $30^{0} C$
Heat lost by the hot water $=$ Heat gained by the cold water.
$m_{1} c Δ T_{1} = m_{2} c Δ T_{2}$
$20 (60 - T) = 60 (T - 20)$
$60 - T = 3 T - 60$
$4 T = 120$
$T = 30^{o} C$