If 21L of milk is to be poured in cartons such that each carton holds 37L of milk- find the number of cartons needed to accomodate all the available milk-

Total nbsp;milk nbsp;= nbsp;21LMilk nbsp;each nbsp;carton nbsp;can nbsp;hold nbsp;= nbsp;37LNumber nbsp;of nbsp;cartons nbsp;= nbsp;To ...

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Standard VII

Mathematics

Percentages

If 21L of mil...

Question

$If 21 L of milk is to be poured in cartons such that each carton holds \frac{3}{7} L of milk, find the number of cartons needed to accomodate all the available milk .$

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Solution

$Total milk = 21 L Milk each carton can hold = \frac{3}{7} L Number of cartons = Total milk \div Milk held by each carton = 21 \div \frac{3}{7} = 21 \times \frac{7}{3} = 49$

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If 21L of milk is to be poured in cartons such that each carton holds 37L of milk, find the number of cartons needed to accomodate all the available milk.

Total milk = 21LMilk each carton can hold = 37LNumber of cartons = Total milk÷Milk held by each carton= 21÷37 = 21×73 = 49

$If 21 L of milk is to be poured in cartons such that each carton holds \frac{3}{7} L of milk, find the number of cartons needed to accomodate all the available milk .$

$Total milk = 21 L Milk each carton can hold = \frac{3}{7} L Number of cartons = Total milk \div Milk held by each carton = 21 \div \frac{3}{7} = 21 \times \frac{7}{3} = 49$