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Molality

If 22 gm be...

Question

If $22 g m$ benzene Present in $100 g m C C l_{4}$ then find the $% W / W$ of benzene in solution:

A

15 %

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B

20 %

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C

12 %

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D

18 %

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Solution

The correct option is C $18 %$
$% W / W = \frac{m a s s}{b e n z e n e} \times 100 = \frac{22}{22 + 100} = \frac{22}{122} \times 100 = 18 %$

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