If 233×121 is divided by 5. What is the remainder?
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is B3 233×121=28,193 We know the divisibility rule for 5: The last digit is 0 or 5. So, here the last digits are not end with 0 or 5. Hence subtract 3 to the number we get 28,193−3=28,190 is divisible by 5. Therefore, remainder is 3.