If 2352-2 P - 3 q - 7 r- frind the values of p - q and rA- 878 - 10-23 mB- 8-78 - 1023 KgC- 87-8 - 10-25 KgD- 8-78 - 1025 Kg

The correct option is D 8.78 × Kg Given 2352 = 2^p × 3^q × 7^r ⇒ 2^4 × 3^1 × 7^2 = 2^p × 3^q × 7^r ⇒ p = 4, q = 1 and r = 2 ...

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Comparison of Quantities Using Exponents

If 2352=2 P ×...

Question

If $2352 = 2^{p} \times 3^{q} \times 7^{r}$ , frind the values of $p, q a n d r$

878 × m

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8.78 × Kg

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87.8 × Kg

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8.78 × Kg

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