If $24 {cm}^{2}$ is area of a rectangular sheet whose dimensions are natural numbers. How many combinations of its length and breadth are possible.

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Solution

We know that area of a rectangular sheet $= lemgth \times breadth$

$24 = 4 \times 6 = 6 \times 4$
$24 = 3 \times 8 = 8 \times 3$
$24 = 2 \times 12 = 12 \times 2$
$24 = 1 \times 24 = 24 \times 1$

Similarly, total $8$ combinations can be made.

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If 24 cm2 is area of a rectangular sheet whose dimensions are natural numbers. How many combinations of its length and breadth are possible.

We know that area of a rectangular sheet =lemgth×breadth 24=4×6=6×4 24=3×8=8×3 24=2×12=12×2 24=1×24=24×1 Similarly, total 8 combinations can be made.

If $24 {cm}^{2}$ is area of a rectangular sheet whose dimensions are natural numbers. How many combinations of its length and breadth are possible.

We know that area of a rectangular sheet $= lemgth \times breadth$

$24 = 4 \times 6 = 6 \times 4$
$24 = 3 \times 8 = 8 \times 3$
$24 = 2 \times 12 = 12 \times 2$
$24 = 1 \times 24 = 24 \times 1$

Similarly, total $8$ combinations can be made.