If 24- 42-16x- then find the value of x

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If 24× 42=16x...

Question

If 2⁴ × 4² =16^x, then find the value of x.

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(4)^{2 x - 1} - (16)^{x - 1} = 384

If $\frac{4^{(x^{2})}}{16^{x}} = 1$ . Find the value of $x$ where $x \neq 0$ .

If $x \times y = x + y + \sqrt{x y}$ , the value of 6 $\times$ 24 is :

∣ ∣ ∣ \begin{matrix} 3 x & 7 - 2 & 4 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 8 & 7 6 & 4 \end{matrix} ∣ ∣ ∣

x

4^{x} - 4^{x - 1} = 24

x

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