Question

If $25-4x\le 16$, find:
(i) the smallest value of $x$, when $x$ is a real number.
(ii) the smallest value of $x$, when $x$ is an integer.

Answer 1

Consider the given equation.

$25-4x\le 16$

$4x\ge 25-16$

$4x\ge 9$

$x\ge \frac{9}{4}$

Thus,

(i) If $x$ is a real number, smallest possible $x=\frac{9}{4}$

(ii) If $x$ is an integer, smallest possible $x=3$