Question

If ${25}^{x+1}=\frac{125}{5^2}$, then find the value of $x$.

Answer 1

${25}^{x+1}=\frac{125}{5^2}$

${25}^{x+1}=5$

$5^{2x+2}=5^1$

Therefore,

$2x+2=1$

$2x=-1$

$x=-\frac{1}{2}$