If 26136 x k is a perfect cube, then the smallest value of k is
11
26136 = 2 x 2 x 2 x 3 x 3 x 3 x 11 x 11
Making triplets, we find that the prime factor 11 do not appear in a group of three.
To make 26136 a perfect cube, we need to multiply it with 11.
Thus, 26136 x 11 is a perfect cube.
Hence, the smallest value of k is 11.