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Question

If 26136 x k is a perfect cube, then the smallest value of k is


A

9

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B

11

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C

4

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D

2

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Solution

The correct option is B

11


26136 = 2 x 2 x 2 x 3 x 3 x 3 x 11 x 11

Making triplets, we find that the prime factor 11 do not appear in a group of three.
To make 26136 a perfect cube, we need to multiply it with 11.
Thus, 26136 x 11 is a perfect cube.

Hence, the smallest value of k is 11.


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