Question

If $27\times 64={(-2)}^a\times 3^b$, then $a-b$ is equal to

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Answer 1

$27=3^3$
$64=2^6={(-2)}^6$
$27\times 64={(-2)}^a\times 3^b$

${(-2)}^6\times 3^3={(-2)}^a\times 3^b$

On comparing the exponents, we get $a=6,b=3$

$a-b=3$