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Question

If 270<A<360,90<B<180,cosA=513,tanB=158, then sin(A+B)=

A
140221
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B
171221
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C
140171
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D
221171
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Solution

The correct option is A 171221

We have,

cosA=513


Then,

sinA=1213


Since,

tanB=158


Then,

cosB=817,sinB=1517


Therefore,

sin(A+B)=sinA.cosB+sinB.cosA


sin(A+B)=1213.817+1517.513


sin(A+B)=96221+75221


sin(A+B)=171221


Hence, this is the answer.


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